Hans Georg Schaathun
Oktober 2016
$$ \int \frac{P(x)}{Q(x)} dx = $$
Finn fylgjande integral $$ \int \frac{1}{x+a} dx = $$
$$u = x+a$$
$$\frac{du}{dx} = 1\quad\quad du = dx$$
$$ I = \int \frac1udu = -\frac1{u^2} + C$$
$$ I = -\frac1{(x+a)^2} + C$$
