Hans Georg Schaathun
September 2016
$$v(t) = 9{,}8t$$
$$x = h(3) - h(2)$$
$$h'(t) = v(t) = 9{,}8t$$
$$x = (4{,}9t^2 + C)\big|_{t=3} - (4{,}9t^2 + C)\big|_{t=2} $$
$$x = 4{,}9\cdot3^2 - 4{,}9\cdot2^2=24{,}5$$
$$x = \int_3^2 v(t)dt$$
